There were 29 more silver beads than blue beads in a packet. Another 93 silver beads and 87 blue beads were put into the packet. How many more silver beads than blue beads were there in the end?
|
Silver |
Blue |
Before |
1 u + 29 |
1 u |
Change |
+ 93 |
+ 87 |
After |
1 u + 122 |
1 u + 87 |
Number of silver beads in the end
= 1 u + 29 + 93
= 1 u + 122
Number of blue beads = 1 u + 87
Number of silver beads more than blue beads in the end
= 122 - 87
= 35
Answer(s): 35