There were 23 more blue small pebbles than red small pebbles in a packet. Another 98 blue small pebbles and 60 red small pebbles were put into the packet. How many more blue small pebbles than red small pebbles were there in the end?
|
Blue |
Red |
Before |
1 u + 23 |
1 u |
Change |
+ 98 |
+ 60 |
After |
1 u + 121 |
1 u + 60 |
Number of blue small pebbles in the end
= 1 u + 23 + 98
= 1 u + 121
Number of red small pebbles = 1 u + 60
Number of blue small pebbles more than red small pebbles in the end
= 121 - 60
= 61
Answer(s): 61