There are thrice as many black blazers as red blazers in a sale. If there are 200 black and red blazers altogether,
- how many black blazers are there?
- how many more black blazers than red blazers?
(a)
Number of red blazers = 1 u
Number of black blazers
= 3 x 1 u
= 3 u
Total number of blazers
= 3 u + 1 u
= 4 u
4 u = 200
1 u = 200 ÷ 4 = 50
Number of black blazers
= 3 u
= 3 x 50
= 150
(b)
Number of more black blazers than red blazers
= 3 u - 1 u
= 2 u
= 2 x 50
= 100
Answer(s): (a) 150; (b) 100