There are four times as many blue windbreakers as gold windbreakers in a sale. If there are 130 blue and gold windbreakers altogether,
- how many blue windbreakers are there?
- how many more blue windbreakers than gold windbreakers?
(a)
Number of gold windbreakers = 1 u
Number of blue windbreakers
= 4 x 1 u
= 4 u
Total number of windbreakers
= 4 u + 1 u
= 5 u
5 u = 130
1 u = 130 ÷ 5 = 26
Number of blue windbreakers
= 4 u
= 4 x 26
= 104
(b)
Number of more blue windbreakers than gold windbreakers
= 4 u - 1 u
= 3 u
= 3 x 26
= 78
Answer(s): (a) 104; (b) 78