There are five times as many black windbreakers as red windbreakers in a sale. If there are 180 black and red windbreakers altogether,
- how many black windbreakers are there?
- how many more black windbreakers than red windbreakers?
(a)
Number of red windbreakers = 1 u
Number of black windbreakers
= 5 x 1 u
= 5 u
Total number of windbreakers
= 5 u + 1 u
= 6 u
6 u = 180
1 u = 180 ÷ 6 = 30
Number of black windbreakers
= 5 u
= 5 x 30
= 150
(b)
Number of more black windbreakers than red windbreakers
= 5 u - 1 u
= 4 u
= 4 x 30
= 120
Answer(s): (a) 150; (b) 120