There are thrice as many gold windbreakers as black windbreakers in a sale. If there are 128 gold and black windbreakers altogether,
- how many gold windbreakers are there?
- how many more gold windbreakers than black windbreakers?
(a)
Number of black windbreakers = 1 u
Number of gold windbreakers
= 3 x 1 u
= 3 u
Total number of windbreakers
= 3 u + 1 u
= 4 u
4 u = 128
1 u = 128 ÷ 4 = 32
Number of gold windbreakers
= 3 u
= 3 x 32
= 96
(b)
Number of more gold windbreakers than black windbreakers
= 3 u - 1 u
= 2 u
= 2 x 32
= 64
Answer(s): (a) 96; (b) 64