There are six times as many red windbreakers as gold windbreakers in a sale. If there are 112 red and gold windbreakers altogether,
- how many red windbreakers are there?
- how many more red windbreakers than gold windbreakers?
(a)
Number of gold windbreakers = 1 u
Number of red windbreakers
= 6 x 1 u
= 6 u
Total number of windbreakers
= 6 u + 1 u
= 7 u
7 u = 112
1 u = 112 ÷ 7 = 16
Number of red windbreakers
= 6 u
= 6 x 16
= 96
(b)
Number of more red windbreakers than gold windbreakers
= 6 u - 1 u
= 5 u
= 5 x 16
= 80
Answer(s): (a) 96; (b) 80