There are six times as many blue windbreakers as silver windbreakers in a sale. If there are 175 blue and silver windbreakers altogether,
- how many blue windbreakers are there?
- how many more blue windbreakers than silver windbreakers?
(a)
Number of silver windbreakers = 1 u
Number of blue windbreakers
= 6 x 1 u
= 6 u
Total number of windbreakers
= 6 u + 1 u
= 7 u
7 u = 175
1 u = 175 ÷ 7 = 25
Number of blue windbreakers
= 6 u
= 6 x 25
= 150
(b)
Number of more blue windbreakers than silver windbreakers
= 6 u - 1 u
= 5 u
= 5 x 25
= 125
Answer(s): (a) 150; (b) 125