A fruit stall had 6 times as many grapefruits as dragonfruits. After 12 dragonfruits were added, the number of grapefruits became twice the number of the dragonfruits. How many dragonfruits were there at the fruit stall at first?
| |
Grapefruits |
Dragonfruits |
| Before |
6x1 =
6 u |
1x1 =
1 u |
| Change |
|
+ 12 |
| After |
2x3 =
6 u |
1x3 =
3 u |
The number of grapefruits remains unchanged. Make the number of grapefruits the same. LCM of 2 and 6 is 6.
Number of dragonfruits added
= 3 u - 1 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of dragonfruits at the fruit stall at first
= 1 u
= 1 x 6
= 6
Answer(s): 6
