A fruit stall had 5 times as many peaches as pears. After 15 pears were added, the number of peaches became twice the number of the pears. How many pears were there at the fruit stall at first?
| |
Peaches |
Pears |
| Before |
5x2 =
10 u |
1x2 =
2 u |
| Change |
|
+ 15 |
| After |
2x5 =
10 u |
1x5 =
5 u |
The number of peaches remains unchanged. Make the number of peaches the same. LCM of 2 and 5 is 10.
Number of pears added
= 5 u - 2 u
= 3 u
3 u = 15
1 u = 15 ÷ 3 = 5
Number of pears at the fruit stall at first
= 2 u
= 2 x 5
= 10
Answer(s): 10
