A fruit stall had 5 times as many dragonfruits as pears. After 21 pears were added, the number of dragonfruits became twice the number of the pears. How many pears were there at the fruit stall at first?
| |
Dragonfruits |
Pears |
| Before |
5x2 =
10 u |
1x2 =
2 u |
| Change |
|
+ 21 |
| After |
2x5 =
10 u |
1x5 =
5 u |
The number of dragonfruits remains unchanged. Make the number of dragonfruits the same. LCM of 2 and 5 is 10.
Number of pears added
= 5 u - 2 u
= 3 u
3 u = 21
1 u = 21 ÷ 3 = 7
Number of pears at the fruit stall at first
= 2 u
= 2 x 7
= 14
Answer(s): 14
