A fruit stall had 6 times as many guavas as kiwis. After 10 kiwis were added, the number of guavas became twice the number of the kiwis. How many kiwis were there at the fruit stall at first?
| |
Guavas |
Kiwis |
| Before |
6x1 =
6 u |
1x1 =
1 u |
| Change |
|
+ 10 |
| After |
2x3 =
6 u |
1x3 =
3 u |
The number of guavas remains unchanged. Make the number of guavas the same. LCM of 2 and 6 is 6.
Number of kiwis added
= 3 u - 1 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
Number of kiwis at the fruit stall at first
= 1 u
= 1 x 5
= 5
Answer(s): 5
