A fruit stall had 6 times as many peaches as guavas. After 8 guavas were added, the number of peaches became twice the number of the guavas. How many guavas were there at the fruit stall at first?
| |
Peaches |
Guavas |
| Before |
6x1 =
6 u |
1x1 =
1 u |
| Change |
|
+ 8 |
| After |
2x3 =
6 u |
1x3 =
3 u |
The number of peaches remains unchanged. Make the number of peaches the same. LCM of 2 and 6 is 6.
Number of guavas added
= 3 u - 1 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Number of guavas at the fruit stall at first
= 1 u
= 1 x 4
= 4
Answer(s): 4
