A fruit stall had 5 times as many peaches as lemons. After 21 lemons were added, the number of peaches became twice the number of the lemons. How many lemons were there at the fruit stall at first?
| |
Peaches |
Lemons |
| Before |
5x2 =
10 u |
1x2 =
2 u |
| Change |
|
+ 21 |
| After |
2x5 =
10 u |
1x5 =
5 u |
The number of peaches remains unchanged. Make the number of peaches the same. LCM of 2 and 5 is 10.
Number of lemons added
= 5 u - 2 u
= 3 u
3 u = 21
1 u = 21 ÷ 3 = 7
Number of lemons at the fruit stall at first
= 2 u
= 2 x 7
= 14
Answer(s): 14
