Raeann had 11 more croissants than Hilda at first. After Raeann ate 3 croissants, she had thrice as many croissants as Hilda in the end. How many croissants did Hilda have?
| |
Hilda |
Raeann |
| Before |
1 u |
1 u + 11 |
| Change |
|
- 3 |
| After |
1 u |
1 u + 8 |
Comparing Hilda
and Raeann in the end |
1 u |
3 u |
The number of croissants that Hilda had remains unchanged.
Number of croissants that Raeann had in the end
= 3 x 1 u
= 3 u
3 u = 1 u + 8
3 u - 1 u = 8
2 u = 8
1 u = 8 ÷ 2 = 4
Number of croissants that Hilda had
= 1 u
= 4
Answer(s): 4
