Michael had 110 coins more than George at first. After Michael had given away 160 of his coins to Luis, George had thrice as many coins as Michael. Find the number of coins Michael had at first.
| |
Michael |
George |
Comparing between
Michael and George |
110 more |
|
| Before |
1 u + 160 |
3 u |
| Change |
- 160 |
|
| After |
1 u |
3 u |
Michael had 110 coins more than George at first.
If 110 more marbles is given to George at first, both will have the same number of marbles.
3 u + 110 = 1 u + 160
3 u - 1 u = 160 - 110
2 u = 50
1 u = 50 ÷ 2 = 25
Number of coins that Michael has at first
= 1 u + 160
= 25 + 160
= 185
Answer(s): 185
