Lee had 138 coins more than Jeremy at first. After Lee had given away 183 of his coins to Gabriel, Jeremy had four times as many coins as Lee. Find the number of coins Lee had at first.
|
Lee |
Jeremy |
Comparing between Lee and Jeremy |
138 more |
|
Before |
1 u + 183 |
4 u |
Change |
- 183 |
|
After |
1 u |
4 u |
Lee had 138 coins more than Jeremy at first.
If 138 more marbles is given to Jeremy at first, both will have the same number of marbles.
4 u + 138 = 1 u + 183
4 u - 1 u = 183 - 138
3 u = 45
1 u = 45 ÷ 3 = 15
Number of coins that Lee has at first
= 1 u + 183
= 15 + 183
= 198
Answer(s): 198