Mr Choy had $611 more than Mr Lee at first. After Mr Lee had spent $421, Mr Choy had 3 times as much money as Mr Lee. Find the amount of money Mr Lee had at first.
| |
Mr Lee |
Mr Choy
|
| Comparing Mr Lee and Mr Choy at first |
|
$611 more |
| Before |
1 u + $421 |
3 u |
| Change |
- $421 |
|
| After |
1 u |
3 u |
After
Amount that Mr Lee has = 1 u
Amount that Mr Choy has = 3 x 1 u = 3 u
Before
Amount that Mr Lee has = 1 u + 421
Amount that Mr Choy has = 3 u
Mr Choy had $611 more than Mr Lee at first.
If another $611 is given to Mr Lee at first, both will have the same amount at first.
3 u = 1 u + 421 + 611
3 u = 1 u + 1032
3 u - 1 u = 1032
2 u = 1032
1 u = 1032 ÷ 2 = 516
Amount that Mr Lee had at first
= 1 u + 421
= 516 + 421
= $937
Answer(s): $937
