Jean and Tiffany had the
same number of sweets at first. Jean gave 10 sweets away to her brother. In the end, Tiffany had three times as many sweets as Jean. How many sweets did Jean have at first?
| |
Jean |
Tiffany |
| Before |
3 u |
3 u |
| Change |
- 10 |
|
| After |
1 u |
3 u |
The number of sweets that Tiffany had remains unchanged.
Number of sweets that Jean gave away
= 3 u - 1 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
Number of sweets that Jean had at first
= 3 u
= 3 x 5
= 15
Answer(s): 15
