Mary and Tina had the
same number of chocolate bars at first. Mary gave 8 chocolate bars away to her brother. In the end, Tina had three times as many chocolate bars as Mary. How many chocolate bars did Mary have at first?
| |
Mary |
Tina |
| Before |
3 u |
3 u |
| Change |
- 8 |
|
| After |
1 u |
3 u |
The number of chocolate bars that Tina had remains unchanged.
Number of chocolate bars that Mary gave away
= 3 u - 1 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Number of chocolate bars that Mary had at first
= 3 u
= 3 x 4
= 12
Answer(s): 12
