Japheth has 384 mini cupcakes and Xavier has 558 mini cupcakes. How many mini cupcakes must Xavier give to Japheth so that Japheth will have 42 more mini cupcakes than Xavier?
| |
Japheth |
Xavier |
Total |
| Before |
384 |
558 |
942 |
| Change |
+ ? |
- ? |
|
| After |
1 u + 42 |
1 u |
942 |
The total number of mini cupcakes remains unchanged after Xavier gives to Japheth.
Total number of mini cupcakes
= 384 + 558
= 942
Total number of mini cupcakes in the end
= 1 u + 1 u + 42
= 2 u + 42
2 u + 42 = 942
2 u = 942 - 42
2 u = 900
1 u = 900 ÷ 2 = 450
Number of mini cupcakes that Xavier must give to Japheth
= 558 - 450
= 108
Answer(s): 108
