David has 345 candy canes and Charlie has 673 candy canes. How many candy canes must Charlie give to David so that David will have 42 more candy canes than Charlie?
| |
David |
Charlie |
Total |
| Before |
345 |
673 |
1018 |
| Change |
+ ? |
- ? |
|
| After |
1 u + 42 |
1 u |
1018 |
The total number of candy canes remains unchanged after Charlie gives to David.
Total number of candy canes
= 345 + 673
= 1018
Total number of candy canes in the end
= 1 u + 1 u + 42
= 2 u + 42
2 u + 42 = 1018
2 u = 1018 - 42
2 u = 976
1 u = 976 ÷ 2 = 488
Number of candy canes that Charlie must give to David
= 673 - 488
= 185
Answer(s): 185
