Liam has 385 sweets and David has 607 sweets. How many sweets must David give to Liam so that Liam will have 42 more sweets than David?
| |
Liam |
David |
Total |
| Before |
385 |
607 |
992 |
| Change |
+ ? |
- ? |
|
| After |
1 u + 42 |
1 u |
992 |
The total number of sweets remains unchanged after David gives to Liam.
Total number of sweets
= 385 + 607
= 992
Total number of sweets in the end
= 1 u + 1 u + 42
= 2 u + 42
2 u + 42 = 992
2 u = 992 - 42
2 u = 950
1 u = 950 ÷ 2 = 475
Number of sweets that David must give to Liam
= 607 - 475
= 132
Answer(s): 132
