Xavier has 460 mini cupcakes and Neave has 672 mini cupcakes. How many mini cupcakes must Neave give to Xavier so that Xavier will have 50 more mini cupcakes than Neave?
| |
Xavier |
Neave |
Total |
| Before |
460 |
672 |
1132 |
| Change |
+ ? |
- ? |
|
| After |
1 u + 50 |
1 u |
1132 |
The total number of mini cupcakes remains unchanged after Neave gives to Xavier.
Total number of mini cupcakes
= 460 + 672
= 1132
Total number of mini cupcakes in the end
= 1 u + 1 u + 50
= 2 u + 50
2 u + 50 = 1132
2 u = 1132 - 50
2 u = 1082
1 u = 1082 ÷ 2 = 541
Number of mini cupcakes that Neave must give to Xavier
= 672 - 541
= 131
Answer(s): 131
