Simon has 446 sweets and Cody has 698 sweets. How many sweets must Cody give to Simon so that Simon will have 44 more sweets than Cody?
|
Simon |
Cody |
Total |
Before |
446 |
698 |
1144 |
Change |
+ ? |
- ? |
|
After |
1 u + 44 |
1 u |
1144 |
The total number of sweets remains unchanged after Cody gives to Simon.
Total number of sweets
= 446 + 698
= 1144
Total number of sweets in the end
= 1 u + 1 u + 44
= 2 u + 44
2 u + 44 = 1144
2 u = 1144 - 44
2 u = 1100
1 u = 1100 ÷ 2 = 550
Number of sweets that Cody must give to Simon
= 698 - 550
= 148
Answer(s): 148