Gabriel has 375 mochi balls and Ken has 557 mochi balls. How many mochi balls must Ken give to Gabriel so that Gabriel will have 48 more mochi balls than Ken?
| |
Gabriel |
Ken |
Total |
| Before |
375 |
557 |
932 |
| Change |
+ ? |
- ? |
|
| After |
1 u + 48 |
1 u |
932 |
The total number of mochi balls remains unchanged after Ken gives to Gabriel.
Total number of mochi balls
= 375 + 557
= 932
Total number of mochi balls in the end
= 1 u + 1 u + 48
= 2 u + 48
2 u + 48 = 932
2 u = 932 - 48
2 u = 884
1 u = 884 ÷ 2 = 442
Number of mochi balls that Ken must give to Gabriel
= 557 - 442
= 115
Answer(s): 115
