Luke has 362 sweets and Reggie has 539 sweets. How many sweets must Reggie give to Luke so that Luke will have 41 more sweets than Reggie?
|
Luke |
Reggie |
Total |
Before |
362 |
539 |
901 |
Change |
+ ? |
- ? |
|
After |
1 u + 41 |
1 u |
901 |
The total number of sweets remains unchanged after Reggie gives to Luke.
Total number of sweets
= 362 + 539
= 901
Total number of sweets in the end
= 1 u + 1 u + 41
= 2 u + 41
2 u + 41 = 901
2 u = 901 - 41
2 u = 860
1 u = 860 ÷ 2 = 430
Number of sweets that Reggie must give to Luke
= 539 - 430
= 109
Answer(s): 109