Julian has 452 lollipops and Pierre has 611 lollipops. How many lollipops must Pierre give to Julian so that Julian will have 51 more lollipops than Pierre?
| |
Julian |
Pierre |
Total |
| Before |
452 |
611 |
1063 |
| Change |
+ ? |
- ? |
|
| After |
1 u + 51 |
1 u |
1063 |
The total number of lollipops remains unchanged after Pierre gives to Julian.
Total number of lollipops
= 452 + 611
= 1063
Total number of lollipops in the end
= 1 u + 1 u + 51
= 2 u + 51
2 u + 51 = 1063
2 u = 1063 - 51
2 u = 1012
1 u = 1012 ÷ 2 = 506
Number of lollipops that Pierre must give to Julian
= 611 - 506
= 105
Answer(s): 105
