Archie has 357 sweets and Oliver has 570 sweets. How many sweets must Oliver give to Archie so that Archie will have 49 more sweets than Oliver?
| |
Archie |
Oliver |
Total |
| Before |
357 |
570 |
927 |
| Change |
+ ? |
- ? |
|
| After |
1 u + 49 |
1 u |
927 |
The total number of sweets remains unchanged after Oliver gives to Archie.
Total number of sweets
= 357 + 570
= 927
Total number of sweets in the end
= 1 u + 1 u + 49
= 2 u + 49
2 u + 49 = 927
2 u = 927 - 49
2 u = 878
1 u = 878 ÷ 2 = 439
Number of sweets that Oliver must give to Archie
= 570 - 439
= 131
Answer(s): 131
