Simon has 433 balls and Liam has 496 balls. How many balls must Liam give to Simon so that Simon will have 55 less balls than Liam?
| |
Simon |
Liam |
Total |
| Before |
433 |
496 |
929 |
| Change |
+ ? |
- ? |
|
| After |
1 u |
1 u + 55 |
929 |
The total number of balls remains unchanged after Liam gives to Simon.
Total number of balls
= 433 + 496
= 929
Total number of balls in the end
= 1 u + 1 u + 55
= 2 u + 55
2 u + 55 = 929
2 u = 929 - 55
2 u = 874
1 u = 874 ÷ 2 = 437
Number of balls that Liam must give to Simon
= 437 - 433
= 4
Answer(s): 4
