Gabriel has 158 balls and Michael has 314 balls. How many balls must Michael give to Gabriel so that Gabriel will have 66 less balls than Michael?
| |
Gabriel |
Michael |
Total |
| Before |
158 |
314 |
472 |
| Change |
+ ? |
- ? |
|
| After |
1 u |
1 u + 66 |
472 |
The total number of balls remains unchanged after Michael gives to Gabriel.
Total number of balls
= 158 + 314
= 472
Total number of balls in the end
= 1 u + 1 u + 66
= 2 u + 66
2 u + 66 = 472
2 u = 472 - 66
2 u = 406
1 u = 406 ÷ 2 = 203
Number of balls that Michael must give to Gabriel
= 203 - 158
= 45
Answer(s): 45
