Pierre has 172 beads and Brandon has 342 beads. How many beads must Brandon give to Pierre so that Pierre will have 60 less beads than Brandon?
| |
Pierre |
Brandon |
Total |
| Before |
172 |
342 |
514 |
| Change |
+ ? |
- ? |
|
| After |
1 u |
1 u + 60 |
514 |
The total number of beads remains unchanged after Brandon gives to Pierre.
Total number of beads
= 172 + 342
= 514
Total number of beads in the end
= 1 u + 1 u + 60
= 2 u + 60
2 u + 60 = 514
2 u = 514 - 60
2 u = 454
1 u = 454 ÷ 2 = 227
Number of beads that Brandon must give to Pierre
= 227 - 172
= 55
Answer(s): 55
