Pierre has 119 beads and Zane has 446 beads. How many beads must Zane give to Pierre so that Pierre will have 71 less beads than Zane?
| |
Pierre |
Zane |
Total |
| Before |
119 |
446 |
565 |
| Change |
+ ? |
- ? |
|
| After |
1 u |
1 u + 71 |
565 |
The total number of beads remains unchanged after Zane gives to Pierre.
Total number of beads
= 119 + 446
= 565
Total number of beads in the end
= 1 u + 1 u + 71
= 2 u + 71
2 u + 71 = 565
2 u = 565 - 71
2 u = 494
1 u = 494 ÷ 2 = 247
Number of beads that Zane must give to Pierre
= 247 - 119
= 128
Answer(s): 128
