Liam has 218 balls and Dylan has 483 balls. How many balls must Dylan give to Liam so that Liam will have 73 less balls than Dylan?
|
Liam |
Dylan |
Total |
Before |
218 |
483 |
701 |
Change |
+ ? |
- ? |
|
After |
1 u |
1 u + 73 |
701 |
The total number of balls remains unchanged after Dylan gives to Liam.
Total number of balls
= 218 + 483
= 701
Total number of balls in the end
= 1 u + 1 u + 73
= 2 u + 73
2 u + 73 = 701
2 u = 701 - 73
2 u = 628
1 u = 628 ÷ 2 = 314
Number of balls that Dylan must give to Liam
= 314 - 218
= 96
Answer(s): 96