Pierre has 127 marbles and Paul has 480 marbles. How many marbles must Paul give to Pierre so that Pierre will have 61 less marbles than Paul?
| |
Pierre |
Paul |
Total |
| Before |
127 |
480 |
607 |
| Change |
+ ? |
- ? |
|
| After |
1 u |
1 u + 61 |
607 |
The total number of marbles remains unchanged after Paul gives to Pierre.
Total number of marbles
= 127 + 480
= 607
Total number of marbles in the end
= 1 u + 1 u + 61
= 2 u + 61
2 u + 61 = 607
2 u = 607 - 61
2 u = 546
1 u = 546 ÷ 2 = 273
Number of marbles that Paul must give to Pierre
= 273 - 127
= 146
Answer(s): 146
