Reggie has 383 chocolate bars and Cody has 729 chocolate bars. How many chocolate bars must Cody give to Reggie so that Reggie will have thrice as many chocolate bars as Cody?
|
Reggie |
Cody |
Total |
Before |
383 |
729 |
1112 |
Change |
+ ? |
- ? |
|
After |
3 u |
1 u |
4 u |
Total number of chocolate bars
= 383 + 729
= 1112
Total number of chocolate bars
= 3 u + 1 u
= 4 u
4 u = 1112
1 u = 1112 ÷ 4 = 278
Number of chocolate bars that Cody must give Reggie
= 729 - 278
= 451
Answer(s): 451