Pierre has 300 lollipops and Cody has 795 lollipops. How many lollipops must Cody give to Pierre so that Pierre will have twice as many lollipops as Cody?
|
Pierre |
Cody |
Total |
Before |
300 |
795 |
1095 |
Change |
+ ? |
- ? |
|
After |
2 u |
1 u |
3 u |
Total number of lollipops
= 300 + 795
= 1095
Total number of lollipops
= 2 u + 1 u
= 3 u
3 u = 1095
1 u = 1095 ÷ 3 = 365
Number of lollipops that Cody must give Pierre
= 795 - 365
= 430
Answer(s): 430