Fred has 303 chocolate bars and Peter has 795 chocolate bars. How many chocolate bars must Peter give to Fred so that Fred will have twice as many chocolate bars as Peter?
|
Fred |
Peter |
Total |
Before |
303 |
795 |
1098 |
Change |
+ ? |
- ? |
|
After |
2 u |
1 u |
3 u |
Total number of chocolate bars
= 303 + 795
= 1098
Total number of chocolate bars
= 2 u + 1 u
= 3 u
3 u = 1098
1 u = 1098 ÷ 3 = 366
Number of chocolate bars that Peter must give Fred
= 795 - 366
= 429
Answer(s): 429