Fabian has 308 lollipops and Xavier has 732 lollipops. How many lollipops must Xavier give to Fabian so that Fabian will have nine times as many lollipops as Xavier?
|
Fabian |
Xavier |
Total |
Before |
308 |
732 |
1040 |
Change |
+ ? |
- ? |
|
After |
9 u |
1 u |
10 u |
Total number of lollipops
= 308 + 732
= 1040
Total number of lollipops
= 9 u + 1 u
= 10 u
10 u = 1040
1 u = 1040 ÷ 10 = 104
Number of lollipops that Xavier must give Fabian
= 732 - 104
= 628
Answer(s): 628