Pierre had $318 and Warren had $118 at first. Each of them bought an identical cardigan and an identical blouse from the same shop. The blouse cost 2 times as much as the cardigan. In the end, Pierre had 3 times as much money as Warren. What was the cost of the cardigan?
|
Pierre |
Warren |
Difference |
Before |
$318 |
$118 |
$200 |
Change |
- 1 cardigan - 1 blouse |
- 1 cardigan - 1 blouse |
|
After |
3 u |
1 u |
2 u |
Since Pierre and Warren bought the same items, the difference in their amounts remains the same.
Difference in the amounts that they had
= 3 u - 1 u
= 2 u
2 u = 318 - 118
2 u = 200
1 u = 200 ÷ 2 = 100
Amount that Warren had in the end
= 1 u
= $100
Cost of 1 cardigan and 1 blouse
= 118 - 1 u
= 118 - 100
= $18
The blouse cost 2 times as much as the cardigan.
Cost of 1 cardigan = 1 p
Cost of 1 blouse = 2 p
Total cost of 1 cardigan and 1 blouse
= 1 p + 2 p
= 3 p
3 p = 18
1 p = 18 ÷ 3 = 6
Cost of the cardigan
= 1 p
= $6
Answer(s): $6