Albert had $234 and Tom had $158 at first. Each of them bought an identical jacket and an identical blazer from the same shop. The blazer cost 4 times as much as the jacket. In the end, Albert had 3 times as much money as Tom. What was the cost of the jacket?
|
Albert |
Tom |
Difference |
Before |
$234 |
$158 |
$76 |
Change |
- 1 jacket - 1 blazer |
- 1 jacket - 1 blazer |
|
After |
3 u |
1 u |
2 u |
Since Albert and Tom bought the same items, the difference in their amounts remains the same.
Difference in the amounts that they had
= 3 u - 1 u
= 2 u
2 u = 234 - 158
2 u = 76
1 u = 76 ÷ 2 = 38
Amount that Tom had in the end
= 1 u
= $38
Cost of 1 jacket and 1 blazer
= 158 - 1 u
= 158 - 38
= $120
The blazer cost 4 times as much as the jacket.
Cost of 1 jacket = 1 p
Cost of 1 blazer = 4 p
Total cost of 1 jacket and 1 blazer
= 1 p + 4 p
= 5 p
5 p = 120
1 p = 120 ÷ 5 = 24
Cost of the jacket
= 1 p
= $24
Answer(s): $24