Xavier had $263 and Bryan had $137 at first. Each of them bought an identical shirt and an identical windbreaker from the same shop. The windbreaker cost 4 times as much as the shirt. In the end, Xavier had 4 times as much money as Bryan. What was the cost of the shirt?
|
Xavier |
Bryan |
Difference |
Before |
$263 |
$137 |
$126 |
Change |
- 1 shirt - 1 windbreaker |
- 1 shirt - 1 windbreaker |
|
After |
4 u |
1 u |
3 u |
Since Xavier and Bryan bought the same items, the difference in their amounts remains the same.
Difference in the amounts that they had
= 4 u - 1 u
= 3 u
3 u = 263 - 137
3 u = 126
1 u = 126 ÷ 3 = 42
Amount that Bryan had in the end
= 1 u
= $42
Cost of 1 shirt and 1 windbreaker
= 137 - 1 u
= 137 - 42
= $95
The windbreaker cost 4 times as much as the shirt.
Cost of 1 shirt = 1 p
Cost of 1 windbreaker = 4 p
Total cost of 1 shirt and 1 windbreaker
= 1 p + 4 p
= 5 p
5 p = 95
1 p = 95 ÷ 5 = 19
Cost of the shirt
= 1 p
= $19
Answer(s): $19