At first, Brandon had twice as many sweets as Charlie. After they each gave away 12 sweets, Brandon had 6 times as many sweets as Charlie. How many sweets did they have altogether at first?
| |
Brandon |
Charlie |
Difference |
| Before |
2x5 =
10 u |
1x5 =
5 u |
1x5 =
5 u |
| Change |
- 12 |
- 12 |
|
| After |
6 u |
1 u |
5 u |
Since they both gave away the same number of sweets, their difference in the number of sweets remains the same. Make the difference in the number of sweets the same. LCM of 1 and 5 is 5.
Number of sweets that each gave away
= 10 u - 6 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of sweets that they had altogether at first
= 10 u + 5 u
= 15 u
= 15 x 3
= 45
Answer(s): 45
