At first, Tim had 18 sweets and Japheth had 6 times as many sweets as Tim. After they each received an equal number of sweets from their buddy, Japheth had four times as many sweets as Tim. How many sweets did their buddy give to both of them altogether?
| |
Tim |
Japheth |
Difference |
| Before |
1x3 =
3 u |
6x3 =
18 u |
5x3 =
15 u |
| Change |
+ 2 u |
+ 2 u |
|
| After |
1x5 =
5 u |
4x5 =
20 u |
3x5 =
15 u |
Since both received an equal number of sweets, the difference in the number of sweets remains unchanged. LCM of 5 and 3 is 15.
3 u = 18
1 u = 18 ÷ 3 = 6
Number of sweets that each received
= 5 u - 3 u
= 2 u
Number of sweets that both of them received altogether
= 2 x 2 u
= 4 u
= 4 x 6
= 24
Answer(s): 24
