Liam and Seth had the same number of cards at first. After Liam had bought another 26 cards and Seth had lost 10 of his cards, Liam had thrice as many cards as Seth. How many cards did each of them have at first?
| |
Seth |
Liam |
| Before |
1 u + 10 |
3 u - 26 |
| Change |
- 10 |
+ 26 |
| After |
1 u |
3 u |
Liam and Seth had the same number of cards at first.
3 u - 26 = 1 u + 10
3 u - 1 u = 10 + 26
2 u = 36
1 u = 36 ÷ 2 = 18
Number of cards that each of them had at first
= 1 u + 10
= 18 + 10
= 28
Answer(s): 28
