Jeremy and Peter had the same number of cards at first. After Jeremy had bought another 34 cards and Peter had lost 8 of his cards, Jeremy had thrice as many cards as Peter. How many cards did each of them have at first?
|
Peter |
Jeremy |
Before |
1 u + 8 |
3 u - 34 |
Change |
- 8 |
+ 34 |
After |
1 u |
3 u |
Jeremy and Peter had the same number of cards at first.
3 u - 34 = 1 u + 8
3 u - 1 u = 8 + 34
2 u = 42
1 u = 42 ÷ 2 = 21
Number of cards that each of them had at first
= 1 u + 8
= 21 + 8
= 29
Answer(s): 29