Eric and Howard had the same number of cards at first. After Eric had bought another 27 cards and Howard had lost 9 of his cards, Eric had thrice as many cards as Howard. How many cards did each of them have at first?
|
Howard |
Eric |
Before |
1 u + 9 |
3 u - 27 |
Change |
- 9 |
+ 27 |
After |
1 u |
3 u |
Eric and Howard had the same number of cards at first.
3 u - 27 = 1 u + 9
3 u - 1 u = 9 + 27
2 u = 36
1 u = 36 ÷ 2 = 18
Number of cards that each of them had at first
= 1 u + 9
= 18 + 9
= 27
Answer(s): 27