Sean and Harry had the same number of cards at first. After Sean had bought another 31 cards and Harry had lost 8 of his cards, Sean had four times as many cards as Harry. How many cards did each of them have at first?
|
Harry |
Sean |
Before |
1 u + 8 |
4 u - 31 |
Change |
- 8 |
+ 31 |
After |
1 u |
4 u |
Sean and Harry had the same number of cards at first.
4 u - 31 = 1 u + 8
4 u - 1 u = 8 + 31
3 u = 39
1 u = 39 ÷ 3 = 13
Number of cards that each of them had at first
= 1 u + 8
= 13 + 8
= 21
Answer(s): 21