Howard and Gabriel had the same number of cards at first. After Howard had bought another 39 cards and Gabriel had lost 9 of his cards, Howard had five times as many cards as Gabriel. How many cards did each of them have at first?
| |
Gabriel |
Howard |
| Before |
1 u + 9 |
5 u - 39 |
| Change |
- 9 |
+ 39 |
| After |
1 u |
5 u |
Howard and Gabriel had the same number of cards at first.
5 u - 39 = 1 u + 9
5 u - 1 u = 9 + 39
4 u = 48
1 u = 48 ÷ 4 = 12
Number of cards that each of them had at first
= 1 u + 9
= 12 + 9
= 21
Answer(s): 21
