Tom and Michael had the same number of cards at first. After Tom had bought another 40 cards and Michael had lost 8 of his cards, Tom had four times as many cards as Michael. How many cards did each of them have at first?
| |
Michael |
Tom |
| Before |
1 u + 8 |
4 u - 40 |
| Change |
- 8 |
+ 40 |
| After |
1 u |
4 u |
Tom and Michael had the same number of cards at first.
4 u - 40 = 1 u + 8
4 u - 1 u = 8 + 40
3 u = 48
1 u = 48 ÷ 3 = 16
Number of cards that each of them had at first
= 1 u + 8
= 16 + 8
= 24
Answer(s): 24
